[1]董云达,尤燕飞..Richardson迭代法的一个常数步长[J].郑州大学学报(工学版),2009,30(03):139-140.[doi:10.3969/j.issn.1671-6833.2009.03.035]
DONG Yunda,You Yanfei.A constant step of Richardson’s iterative method[J].Journal of Zhengzhou University (Engineering Science),2009,30(03):139-140.[doi:10.3969/j.issn.1671-6833.2009.03.035]
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Richardson迭代法的一个常数步长(
)
《郑州大学学报(工学版)》[ISSN:1671-6833/CN:41-1339/T]
- 卷:
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30卷
- 期数:
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2009年03期
- 页码:
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139-140
- 栏目:
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- 出版日期:
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1900-01-01
文章信息/Info
- Title:
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A constant step of Richardson’s iterative method
- 作者:
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董云达; 尤燕飞.
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郑州大学,数学系,河南,郑州,450001, 南京大学,数学系,江苏,南京,210093
- Author(s):
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DONG Yunda; You Yanfei
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- 关键词:
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正定线性方程组; Richardson迭代法; 步长; 收敛
- Keywords:
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- DOI:
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10.3969/j.issn.1671-6833.2009.03.035
- 文献标志码:
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A
- 摘要:
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对于求解对称正定线性方程组的Richardson迭代法,给出一个新的常数步长.它仅依赖于系数矩阵的对角线上的最小元素和最大特征值.而且,还证明了在该步长下Richardgon迭代法产生的梯度模序列线性地趋于0.初步的数值试验表明了新步长的某些优势.
- Abstract:
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For the Richardson iterative method for solving systems of symmetric positive definite linear equations, a new constant step is given. It relies only on the minimum element and maximum eigenvalues on the diagonal of the coefficient matrix. Moreover, it is also proved that the gradient modulus sequence generated by the Richardgon iterative method tends linearly to 0 at this step.
更新日期/Last Update:
1900-01-01